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25x^2-108x+9^2=0
We add all the numbers together, and all the variables
25x^2-108x+81=0
a = 25; b = -108; c = +81;
Δ = b2-4ac
Δ = -1082-4·25·81
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-18\sqrt{11}}{2*25}=\frac{108-18\sqrt{11}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+18\sqrt{11}}{2*25}=\frac{108+18\sqrt{11}}{50} $
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